The number of oxalic acid molecules in 100 ml of 0.02 N oxalic acid is

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The number of oxalic acid molecules in 100 ml of 0.02 N oxalic acid is

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$6 .023 \times 10^{20}$

$6 .023 \times 10^{21}$

$6 .023 \times 10^{22}$

$6 .023 \times 10^{23}$

answer is A.

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Detailed Solution

$\begin{array}{l} Normality = Molarity \times Valence factor \\ ∴ Molarity = \frac{Normality}{Valence factor} \\ Valence factor for oxalic acid \\ = \frac{mol . wt . of oxalic acid}{Eq . wt . of oxalic acid} \\ = \frac{mol . wt . of oxalic acid}{mol . wt . of oxalic acid} \times 2 = 2 \\ (As basicity of oxalic acid is 2 & E = \frac{Mol . wt .}{2}) \\ Molarity = \frac{20}{2} = 0 .01 \\ Number of millimoles = 0 .01 \times 100 \\ Number of moles = 0 .001 \\ ∴ Number of oxalic acid molecules = 0 .001 \times 6 .023 \times 10^{23} \\ = 6 .023 \times 10^{20} \end{array}$