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Q.

The number of oxygen atoms in $4.4 g$ of ${CO}_{2}$ is approx

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a

$1.2 \times 10^{23}$

b

$6 \times 10^{22}$

c

$6 \times 10^{23}$

d

$12 \times 10^{23}$

answer is A.

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Detailed Solution

$4.4 g$ of ${CO}_{2}$ has $2 \times 6 \times 10^{23}$ atoms of oxygen

$4.4 g$ of ${CO}_{2}$ has $= \frac{12 \times 10^{23}}{44} \times 4.4 = 1.2 \times 10^{23}$ atoms

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