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Q.

The number of paired and unpaired electrons in the valence shell of the members of oxygen family are

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a

3 and 3

b

2 and 3

c

4 and 2

d

2 and 4

answer is A.

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Detailed Solution

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the electron configurations of these elements are:

  • Oxygen (O): 1s² 2s² 2p⁴
  • Sulfur (S): 1s² 2s² 2p⁶ 3s² 3p⁴
  • Selenium (Se): 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁴
  • Tellurium (Te): 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁴
  • Polonium (Po): 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰ 6p⁴

Based on their electron configurations, the members of the oxygen family have four valence electrons in the outermost shell. These electrons can be represented as two pairs of electrons (i.e., two lone pairs) and two unpaired electrons.

Thus, the number of paired and unpaired electrons in the valence shell of the members of the oxygen family is as follows:

  • Oxygen (O): 2 paired electrons and 2 unpaired electrons
  • Sulfur (S): 2 paired electrons and 2 unpaired electrons
  • Selenium (Se): 2 paired electrons and 2 unpaired electrons
  • Tellurium (Te): 2 paired electrons and 2 unpaired electrons
  • Polonium (Po): 2 paired electrons and 2 unpaired electrons
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