The number of particles is given by n=−Dn2−n1x2−x1crossing a unit area ⊥to X-axis in unit time, where n1 and n2, are number of particles per unit volume for the value of x1, and x2. Find dimensions of D called as diffusion constant

Dimensional formula for n=L−2T−1Dimensional formula of n1 or n2=L−3Now, D=−nx2−x1n2−n1or , =L−2T−1[L]L−3=L2T−1=M0L2T−1

The number of particles is given by n=−Dn2−n1x2−x1crossing a unit area ⊥to X-axis in unit time, where n1 and n2, are number of particles per unit volume for the value of x1, and x2. Find dimensions of D called as diffusion constant

Dimensional formula for n=L−2T−1Dimensional formula of n1 or n2=L−3Now, D=−nx2−x1n2−n1or , =L−2T−1[L]L−3=L2T−1=M0L2T−1

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

The number of particles is given by $n = - D \frac{n_{2} - n_{1}}{x_{2} - x_{1}}$ crossing a unit area $⊥$ to X-axis in unit time, where n₁ and n₂, are number of particles per unit volume for the value of x₁, and x₂. Find dimensions of D called as diffusion constant

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

M^o LT²

M^oL²T^{- 4}

M^oLT^-3

M^o L² T^-1

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Dimensional formula for $n = [L^{- 2} T^{- 1}]$
Dimensional formula of $n_{1} or n_{2} = [L^{- 3}]$
Now, $D = - n \frac{(x_{2} - x_{1})}{(n_{2} - n_{1})}$
or , $\begin{matrix} = \frac{[L^{- 2} T^{- 1}] [L]}{[L^{- 3}]} = [L^{2} T^{- 1}] \\ = [M^{0} L^{2} T^{- 1}] \end{matrix}$