The number of particles (n) crossing a unit area perpendicular to the x-axis per unit time is given by n=−Dn2−n1x2−x1 where n1 and n2 are the number of particles per unit volume for x equal to x1 and x2 respectively. The dimensions of D (called diffusion constant) are

n=−Dn2−n1x2−x1⇒L−2T−1=DL−3[L]⇒D=L2T−1D=MoL2T−1

The number of particles (n) crossing a unit area perpendicular to the x-axis per unit time is given by n=−Dn2−n1x2−x1 where n1 and n2 are the number of particles per unit volume for x equal to x1 and x2 respectively. The dimensions of D (called diffusion constant) are

n=−Dn2−n1x2−x1⇒L−2T−1=DL−3[L]⇒D=L2T−1D=MoL2T−1

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The number of particles (n) crossing a unit area perpendicular to the x-axis per unit time is given by $n = - D (\frac{n_{2} - n_{1}}{x_{2} - x_{1}})$ where n₁ and n₂ are the number of particles per unit volume for x equal to x₁ and x₂ respectively. The dimensions of D (called diffusion constant) are

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$M^{0} L^{2} T^{- 1}$

${ML}^{2} T^{- 4}$

$M^{0} L^{2} T^{- 2}$

$M^{0} {LT}^{- 1}$

answer is A.

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$n = - D (\frac{n_{2} - n_{1}}{x_{2} - x_{1}}) \Rightarrow L^{- 2} T^{- 1} = \frac{D [L^{- 3}]}{[L]} \Rightarrow D = L^{2} T^{- 1}$

$[D] = [M^{o} L^{2} T^{- 1}]$

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The number of particles (n) crossing a unit area perpendicular to the x-axis per unit time is given by n=−Dn2−n1x2−x1 where n1 and n2 are the number of particles per unit volume for x equal to x1 and x2 respectively. The dimensions of D (called diffusion constant) are

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