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Q.

The number of photons emitted per second by a Medium wave transmitter of 10 kW power, emitting radio waves of wavelength 500m

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a

1.51 × 10³¹

b

71.51 × 10³¹

c

9.51 × 10³¹

d

2.51 × 10³¹

answer is A.

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Detailed Solution

$If n is the no . of photons per \sec then power P = \frac{nhc}{λ}$

$n = \frac{Pλ}{hc}$

$n = \frac{10 \times 10^{3} \times 500}{6.6 \times 10^{- 34} \times 3 \times 10^{8}} \approx 2.5 \times 10^{31}$

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