The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of 3.3 x 10-3 watt will be : (h = 6.6 x 10-34 Js)

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The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of 3.3 x 10^-3 watt will be : (h = 6.6 x 10^-34 Js)

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Detailed Solution

The number of protons delivered per second is given by
$\begin{array}{l} \frac{n}{t} = \frac{IAλ}{hc} = \frac{Pλ}{hc} \Rightarrow \frac{n}{t} = \frac{3 .3 \times 10^{- 3} \times 600 \times 10^{- 9}}{3 \times 10^{8} \times 6 .6 \times 10^{- 34}} \\ \frac{n}{t} = 10^{16} \end{array}$