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The number of points of discontinuity of $f (x) = [x^{3} + 1]$ in $(1, 2)$ is /are (where $[•]$ denote the gratest integer)

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$1$

$6$

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$4$

answer is B.

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Detailed Solution

$x \in (1, 2) \Rightarrow x^{3} + 1 \in (2, 9)$
$\Rightarrow [x^{3} + 1] = 3 t o 8$

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