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Q.

The number of S – S bonds in the product formed by the oxidation of hypo with iodine.

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answer is 3.

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Detailed Solution

$2 {Na}_{2} S_{2} O_{3} + I_{2} \to {Na}_{2} S_{4} O_{6} + 2 NaI$
Structure of ${Na}_{2} S_{4} O_{6}$ is
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The number of S – S bonds in the product formed by the oxidation of hypo with iodine.