The number of sigma and pi bonds present in a molecule of ${\mathrm{XeO}}_3{\mathrm{F}}_2$ are x and y. The ratio of y and x is

In  ${\mathrm{XeO}}_3{\mathrm{F}}_2$

Total number of electron pair $=\frac{8+0+2}{2}=5$

Total number of bond pair $=5$

Total number of lone pair $=(5-5)=0$

Hybridization $={\mathrm{sp}}^3 \mathrm{d}$

Thus, the predicted shape is trigonal bipyramidal.

Number of sigma bond $=5=x$

Number of pi bond =3=y

$\Rightarrow \frac{\mathrm{y}}{\mathrm{x}}=\frac{3}{5}=0.6$

Hence, the ratio of y and x is 0.6.