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The number of sulphur atoms present in 0.2 mole of sodium thiosulphate is (N=Avogadro number)

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0.2N

0.4N

0.1N

answer is C.

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Detailed Solution

sodium thiosulphate is Na₂S₂O₃

One mole of Na₂S₂O₃ contains 2N sulphur atoms

The number of sulphur atoms present in 0.2 mole of Na₂S₂O₃ = 0.2 $\times$ 2N=0.4N

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