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The number of tangents that can be drawn frorn $(6, 0)$ to the circle; $x^{2} + y^{2} - 4 x - 6 y - 12 = 0$ are

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answer is C.

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Detailed Solution

Let $S \equiv x^{2} + y^{2} - 4 x - 6 y - 12 = 0$

$S (6, 0) = 36 + 0 - 24 - 6 (0) - 12 = 0 \Rightarrow (6, 0)$ lies on $S = 0$

One tangent can be drawn from (6, 0) to $S = 0$

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