The number of tangents that can be drawn frorn$(6,0)$ to the circle; $x^2+y^2-4x-6y-12=0$ are

Let $S\equiv x^2+y^2-4x-6y-12=0$

$S(6,0)=36+0-24-6\left(0\right)-12=0\Rightarrow (6,0)$ lies on $S= 0$

One tangent can be drawn from (6, 0) to $S= 0$