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The number of tetrahedral voids in the unit cell of a face-centred cubic lattice of similar atoms is

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answer is C.

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Detailed Solution

In face centered cubic unit cell (FCC), tetrahedral voids are present on body diagonals. There are two tetrahedral voids on each body diagonal at $(\frac{1}{4})$ th of the distance from each corner.

So, total number of tetrahedral voids = (no. of tetrahedral voids per body diagonal) x (no. of body diagonals) = 2×4=8

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