The number of turns in the coil of an AC generator is 5000 and the area of the coil is 0.25 m2. The coil is rotated at the rate of 100 cycles/sec in a magnetic field of 0.2 T. The peak value of the emf (in kV) generated is[Take π=3.14]

ϵ0=ωNBAϵ0=2×3.14×100×5000×0.2×0.25ϵ0=157 kV

Book Online Demo

Check Your IQ

Try Test

Courses

The number of turns in the coil of an AC generator is 5000 and the area of the coil is 0.25 m². The coil is rotated at the rate of 100 cycles/sec in a magnetic field of 0.2 T. The peak value of the emf (in kV) generated is
[Take $π = 3.14$ ]

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 157.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

$ϵ_{0} = ωNBA$

$ϵ_{0} = 2 \times 3.14 \times 100 \times 5000 \times 0.2 \times 0.25$

$ϵ_{0} = 157 kV$

Watch 3-min video & get full concept clarity