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Q.

The number of turns in the coil of an ac generator is 5000 and the area of the coil is 0.25 m2. The coil is rotated at the rate of 100 cycles/sec in a magnetic field of 0.2 T. The peak value of the emf generated is nearly 
 

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a

786 kV 
 

b

440 kV 
 

c

220 kV 
 

d

157.1 kV 
 

answer is D.

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Detailed Solution

Given data:  AC generator is 5000Area of the coil is 0.25 m2.

Concept used: Alternating current 

Detailed solution:

magnetic flux linked with the coil ϕ=NABcosωt

induced emf e=-dt=NABωsinωt Maximum emf=NABω

e0=2×3.14×100×5000×0.2×0.25 e0=157kV

 

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