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The number of unit cells in 58.5 gm of NaCl is approximately

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6 × 10²⁰

1.5 × 10²³

6 × 10²³

0.5 × 10²⁴

answer is B.

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Detailed Solution

$4 (N a^{+} C l^{-}) \to$ 1 unit cel
4 moles $(N a C l) \to 6 \times 10^{23}$ unit cel
$4 \times 58.5 g m N a C l \to 6 \times 10^{23}$
$58.5 g m N a C l \to ?$
$= \frac{58.5 \times 6 \times 10^{23}}{4 \times 58.5} = 1.5 \times 10^{23}$

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