The number of unpaired electron in [Pt(CN)₄]^2– ion having square planar geometry (At.No. of Pt = 78) is

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answer is A.

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Detailed Solution

In this complex, Pt is in the +2 state. It forms a square planar structure. This means that it undergoes dsp² hybridization. Now, the electronic configuration of Pd(+2) is 5d⁸.

CN⁻ being a strong field ligand causes the pairing of unpaired electrons. Hence, there are no unpaired electrons in

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