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Q.

The number of ways in which 10 persons can go in two boats, so that there may be 5 on each boat, supposing that two particular persons will not go in the same boat is 
 

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a

12C5   10

b

2×C4   8

c

C4   8

d

12C5   8

answer is C.

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Detailed Solution

Two particular persons can be in different boats in 2 ways

Then the remaining 8 persons can be divided into two groups containing 4 each is  8C4

ways

Therefore required number= 8C4×2

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