The number of ways in which 5 boys and 4 girls sit around a circular table so that no two girls sit together is

5 boys around a round table can be arranged in $\left(5-1\right)!$=$\text{4!}$ ways

In the 5 gaps ,the 4girls can be arranged in${ }^{\text{5}}{\text{p}}_{\text{4}}$  ways

 ${\text{=4!}}^{\text{5}}{\text{p}}_{\text{4}}\text{=4!5! }$