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Q.

The number of ways of 5-letters put in 5 addressed envelopes so that one letter is in right envelope and all the remaining are placed in wrong envelopes is

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a

35

b

25

c

50

d

45

answer is C.

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Detailed Solution

$5 \times 4! [1 - \frac{1}{1!} + \frac{1}{2!} - \frac{1}{3!} + \frac{1}{4!}] = 45$

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