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The number of ways of arranging 3 boys and 4 girls so that no boy is in between any two girls is

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576

3!4!

$4! \times {}^{5}P_{3}$

answer is C.

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Detailed Solution

consider 4 girls as one unit. 3 boys and girls unit can be arranged in 4! ways. Girls can be arranged among them in 4! ways

total number of arrangements=4!(4!)=576

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