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The number of zeros of the following quadratic polynomial are:
4s2 − 4s + 1

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answer is B.

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Detailed Solution

4s2 − 4s + 1
To find the zeros of the quadratic polynomial we consider
4s2 − 4s + 1 = 0
4s2 − 2s – 2s + 1 = 0
2s(2s – 1) -1(2s – 1) = 0
(2s – 1)(2s – 1) = 0
2s – 1 = 0 and 2s – 1 = 0
2s = 1 and 2s = 1
s =

\frac{1}{2}

and s =

\frac{1}{2}

Then, The zeroes of the polynomial =

\frac{1}{2}

and

\frac{1}{2}

Hence, the number of zeroes is 2

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