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Q.

The number of zygotic combinations possible in a cross AABBCcDd x AAbbCcDD are 

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a

8

b

16

c

64

d

32

answer is B.

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Detailed Solution

No of heterozygotes in parent AABBCcDd  is 2, so types of gametes it can produce is 2 2  = 4.

No of heterozygotes in parent  AAbbCcDD  is 1, so types of gametes it can produce is 2 1  = 2 .

Total no of zygotic combinaitons possible are 4 multiplied by 2 =8.

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