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Q.

The number of ${Cl}^{-} and {Ca}^{+ 2}$ ions respectively in 222g. of ${CaCl}_{2}$ are

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a

$2 N_{A}, 4 N_{A}$

b

$2 N_{A}, 1 N_{A}$

c

$1 N_{A}, 2 N_{A}$

d

$4 N_{A}, 2 N_{A}$

answer is A.

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Detailed Solution

$M . Wt of {CaCl}_{2} = 40 + 71 = 111 grams$
$1 mole {CaCl}_{2} = 1 m o l e \underset{(N)}{{Ca}^{+ 2}} & 2 \underset{(2 N)}{mole} {Cl}^{-}$

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The number of Cl−and Ca+2 ions respectively in 222g. of CaCl2 are