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Q.

The numbers of non-zero terms in the expansion of (1+32x)9+(132x)9 is:

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a

9

b

0

c

5

d

10

answer is C.

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Detailed Solution

(1+32x)9+(132x)9=2 9C0+9C2(32x)2+9C4(32x)4++9C8(32x)8

number of non-zero terms =5

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