Q.

The numbers of terms in the expansion of (a+b+c)n , where nN , is

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a

(n+1)(n+2)2

b

n+1

c

n+2

d

(n+1)n

answer is A.

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Detailed Solution

(a+(b+c))n=an+nC1an1(b+c)1+nC2an2(b+c)2+....+nCn(b+c)n

Further expanding each term of R.H.S.

First term on expansion given one term

Second term on expansion gives two terms

Third term on expansion gives three terms and so on.

 Total no. of terms =1+2+3+....+(n+1)=(n+1)(n+2)2

Hence (A) is the correct answer.

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