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The numerator of a fraction is 6 less than the denominator if 3 is added to the numerator, the fraction is equal to $\frac{2}{3}$ , then the original fraction is

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$\frac{1}{2}$

$\frac{2}{3}$

$\frac{3}{9}$

$\frac{4}{9}$

answer is C.

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Detailed Solution

$\frac{x - 6}{x} \to Original fraction$

$\frac{x - 6 = 3}{x} = \frac{2}{3}$

$3 x - 9 = 2 x$

$x = 9, x - 6 = 3$

$\frac{x - 6}{x} = \frac{3}{9}$

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