The observed dipole moment of HCl molecule is 1.03 D. If HCl bond distance is 1.275 Å. The % ionic character in HCl is

$\begin{array}{l}\text{ Dipole moment }\mu =\text{ charge }\left(q\right)\times \text{ distance }\\ 1.03\times {10}^{-18}=\text{ charge }\times 1.275\times {10}^{-8}\\ \text{ Charge }=\frac{1.03\times {10}^{-18}}{1.275\times {10}^{-8}}\\ \text{ Percentage ionic character }\frac{1.03\times {10}^{-18}\times 100}{1.275\times 4.8\times {10}^{-10}\times {10}^{-8}}\end{array}$