The observed rotation of 2.0gm of a compound in 10mL solution in a 25cm long polarimeter tube is $+ {13.4}^{0}$ . The specific rotation of compound is:

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$+ {40.2}^{0}$

$- {26.8}^{0}$

$+ {26.8}^{0}$

$+ {30.2}^{0}$

answer is C.

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Detailed Solution

${[θ]}_{T}^{λ} = \frac{θ_{o b s}}{C \times l}$
$C =$ concentration in gm/mL
$l =$ length of tube in decimeter
${[θ]}_{T}^{λ} = \frac{+ 13.4}{0.2 \times 2.5} = + {26.8}^{0}$

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