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Q.

The odds against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5 then the probability that at least one event will happen is

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answer is 0.66.

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Detailed Solution

P(A):P(A)=5:2⇒P(A)=27 and P(B):P(B)=3:5⇒P(B)=38  ⇒P(A)=27,P(B)=38 ∴P(A∪B)=P(A)+P(B)-PA∩B ⇒P(A∪B)=27+38-0=3756

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The odds against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5 then the probability that at least one event will happen is