The one that has pseudo-octet configuration

$\begin{array}{rl} & {\mathrm{Mn}}^{2+}-1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^{5}4{\mathrm{s}}^0 - 13\\ & {\mathrm{Cu}}^{2+}-1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^{9 }4{\mathrm{s}}^0 -17\\ & {\mathrm{Zn}}^{2+}-1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^{10}4{\mathrm{s}}^0 - 18\\ & {\mathrm{Cr}}^{ 2+}-1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^{4}4{\mathrm{s}}^0- 12\end{array}$

Any element that has an outermost electronic configuration of s²p⁶d¹⁰ instead of s²p⁶ is known to have a pseudo-noble gas electron configuration.

Hence, the correct option is option (C).