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Q.

The optical rotation of an optically active compound is +20° the length of tube 10 cm and the density of solution is 0.4 g L-1. The specific rotation of  the compound is

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a

+5°

b

+0.5°

c

+50°

d

+500°

answer is A.

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Detailed Solution

10 cm =1dm (specific rotation [α]Dl=θl×c)

[α]=+2001×0.4=+500

Where  l = length of tube in decimeter
c=concentration of solution in g/ml
D=Wave length
θ = optical rotation

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