The orbit and orbital angular momentum of an electron are $\frac{3\mathrm{h}}{2\mathrm{\pi }}$ and $\sqrt{\frac{3}{2}}\frac{\mathrm{h}}{\mathrm{\pi }}$ respectively.The number of radial and angular nodes for the orbital in which the electron is present are respectively.

$$\begin{gathered} \mathrm{Orbit} \mathrm{angular} \mathrm{momentum} =\frac{\mathrm{nh}}{2\mathrm{\pi }}=\frac{3\mathrm{h}}{2\mathrm{\pi }} \\ \mathrm{Thus} \mathrm{n}=3,\mathrm{hence} \mathrm{orbit} \mathrm{is} 3 \\ \mathrm{Orbital} \mathrm{angular} \mathrm{momentum}=\sqrt{\mathrm{l}\left(\mathrm{l}+1\right)} \frac{\mathrm{h}}{2\mathrm{\pi }}=\sqrt{\frac{3}{2}}.\frac{\mathrm{h}}{\mathrm{\pi }} \\ \mathrm{we} \mathrm{can} \mathrm{conclude} \mathrm{that} \mathrm{l}=2, \mathrm{hence} \mathrm{the} \mathrm{orbital} \mathrm{is} 3\mathrm{d} \\ \mathrm{Number} \mathrm{of} \mathrm{radial} \mathrm{nodes}=\mathrm{n}-\mathrm{l}-1=3-2-1=0 \\ \mathrm{Number} \mathrm{of} \mathrm{angular} \mathrm{nl}=\mathrm{l}=2 \end{gathered}$$