The orbital angular momentum of a satellite is L, when it is revolving in a circular orbit at height h from earth surface. If the distance of satellite from the earth centre is increased by eight times to its initial value, then the new angular momentum will be

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answer is C.

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Detailed Solution

$L = m \sqrt{\frac{GM}{r}} \cdot r \Rightarrow L \propto \sqrt{r}$
Radius is increased by 8 times
$r_{f} = 9 r$
$\frac{L_{f}}{L_{i}} = \sqrt{\frac{r_{f}}{r_{i}}}$

$\Rightarrow L_{f} = \sqrt{9} L = 3 L$

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