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Q.

The orbital involved in hybridization $(s p^{3} d)$ of trigonalbipyramidal geometry is

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a

$d_{x z}$

b

$d_{x^{2} - y^{2}}$

c

$d_{x^{2}}$

d

$d_{x y}$

answer is B.

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Detailed Solution

Square pyramidal $\to d_{x^{2} - y^{2}}$ ; trigonal bipyramidal $\to d_{z^{2}}$

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