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Q.

The orbital speed of an artificial satellite very close to the surface of the earth is V₀. Then the orbital speed of another artificial satellite at a height equal to three times the radius of the earth is

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a

$4 V_{o}$

b

$2 V_{o}$

c

$3 V_{o}$

d

$0 .5 V_{o}$

answer is C.

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Detailed Solution

$v \propto \frac{1}{\sqrt{r}}, If r = R then v = V_{0}$

$If r = R + h = R + 3 R = 4 R then v = \frac{V_{0}}{2} = 0 .5 V_{0}$

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