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The orbital speed of electron in the ground state of hydrogen is $υ$ . Its orbital speed when it is excited to the energy state – 3.4ev is

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$\frac{υ}{8}$

$\frac{υ}{4}$

$2 υ$

$\frac{υ}{2}$

answer is B.

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Detailed Solution

As $υ = \frac{C}{137} . \frac{Z}{n}$

$υ α \frac{1}{n}$

Given $n = 1 υ = υ$
And $n = 2 υ = ?$

$\frac{υ_{1}}{υ_{2}} = \frac{n_{2}}{n_{1}}$

$\begin{array}{l} \frac{υ}{υ_{1}} = \frac{2}{1} \\ υ^{1} = \frac{υ}{2} \end{array}$

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