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The orbital velocity of electron in the ground state is v. If the electron is excited to energy state - 0.54 eV its orbital velocity will be

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$\frac{v}{3}$

$\frac{v}{5}$

$\frac{v}{7}$

answer is C.

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Detailed Solution

$\begin{array}{l} E_{n} = - \frac{13 .6}{n^{2}} or n^{2} = - \frac{13 .6}{- 0 .54} \\ or n^{2} = 25 .2 or n = 5 (nearly) \\ No, v_{n} = \frac{v}{5} \end{array}$

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