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The orbital which has two radial nodes and sum of radial and angular nodes is five is

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answer is B.

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Detailed Solution

Orbital	Number of radial nodes (n-l-1)	Number of angular nodes (l)	Total nodes
4d	4-2-1 = 1	2	3
6f	6-3-1 = 2	3	5
7s	7-0-1 = 6	0	6
5p	5-1-1 = 3	1	4

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