Q.

The orbital with 4 radial and 1 angular nodes is 

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a

6pz 

b

4dxy

c

5py 

d

5dxy

answer is B.

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Detailed Solution

Radial nodes =n¬ l- -1
Angular node = l
Where, n = Principile quantum number.
l   = Azimuthal quantum number.
For 5py, n = 5,  l = 1
 Radial node = 5 – 1 – 1 = 3
 Angular node = 1
For 6pz, n = 6,  l = 1
 Radial node = 6 – 1 – 1 = 4
 Angular node = 1 
For 4dxy, n = 4, l = 2
 Radial node = 4 – 2 – 1 = 1
 Angular node = 2
For 5dyz, n = 5, l = 2
 Radial node = 5 – 2 – 1 =2
 Angular node = 2
Hence, the orbital node 4 radial and 1 angular nodes is 6p
 

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