The order of covalent characters of KF, KI, and KCl is

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$KF < KCl < KI$

$KF < KI < KCl$

$KCl < KF < KI$

$KI < KCl < KF$

answer is D.

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Detailed Solution

The increasing order of covalent characters of KF, KI, and KCl is $KF < KCl < KI$ .
It is because the greater the size of the anion higher will be the covalent character. Iodide has the largest size among the given anions.

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