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The order of decreasing ionization enthalpy in alkali metals is

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Na > Li > K > Rb

Rb < Na < K < Li

Li > Na > K > Rb

K < Li < Na < Rb

answer is C.

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Detailed Solution

As the size increases the attractive force on the valency e^- decreases, therefore removal of electrons is easier, and hence IE decreases

IE Order = Li>Na>K>Rb>Cs

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