The order of screening effect of electrons of $s, p, d$ and $f$ orbitals of a given shell of an atom on its outer shell electrons is :

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$s > p > d > f$

$f > p > s > d$

$f > d > p > s$

$p < d < s > f$

answer is A.

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Detailed Solution

The order of the screening effect of the electrons in the s, p, d, and f orbitals of a given atom's shell on the electrons in its outer shell is s > p > d > f.
The subshell that is closer to the nucleus has more penetrating power and the screening effect for the same amount of n, and the order of penetrating power is s > p > d > f. Therefore, due to its effective charge density, s has the greatest impact on reducing the force of attraction between the outermost electron and nucleus, followed by p, d, and f in that order.

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