The order of stability of metal oxides is

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${Fe}_{2} O_{3} < {Al}_{2} O_{3} < {Cr}_{2} O_{3} < MgO$

${Al}_{2} O_{3} < MgO < {Fe}_{2} O_{3} < {Cr}_{2} O_{3}$

${Cr}_{2} O_{3} < MgO < {Al}_{2} O_{3} < {Fe}_{2} O_{3}$

${Fe}_{2} O_{3} < {Cr}_{2} O_{3} < {Al}_{2} O_{3} < MgO$

answer is B.

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Detailed Solution

The Ellingham graph is plotted between $∆ G$ and temperature. It shows the stability of the dependency of temperature on the stability of the compound. It is widely used in metallurgy process. The compounds that are present in the lower position of the graph has a negative $∆ G$ value, thereby are highly stable compounds.

Among the given compounds, MgO is present at the lowest position, hence it is highly stable. Al₂O₃ present above MgO, therefore its stability is lesser than MgO. Cr₂O₃ present above Al₂O₃ but below Fe₂O₃.

Trend of the stability of metal oxide is:

${Fe}_{2} O_{3} < {Cr}_{2} O_{3} < {Al}_{2} O_{3} < MgO$ .