The origin is shifted to (1, 2), the equation y2 –8x– 4y + 12=0 changes to Y2 + 4aX = 0 then a =

x=X+1,y=Y+2. Substituing x,y in y2 – 8x – 4y + 12 = 0 then⇒Y2−8X=0 compare with Y2+4aX=0⇒4a=−8⇒a=−2

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The origin is shifted to (1, 2), the equation y² –8x– 4y + 12=0 changes to Y² + 4aX = 0 then a =

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answer is -2.

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Detailed Solution

$x = X + 1, y = Y + 2 .$
Substituing x,y in y² – 8x – 4y + 12 = 0 then
$\begin{array}{l} \Rightarrow Y^{2} - 8 X = 0 c o m p a r e w i t h Y^{2} + 4 a X = 0 \\ \Rightarrow 4 a = - 8 \Rightarrow a = - 2 \end{array}$

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