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The orthocenter of a triangle formed by the line $x + y = 3$ and pair of lines $6 x^{2} - 10 x y - 6 y^{2} + 2 x + 6 y - 9 = 0$ is

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$(\frac{13}{169}, \frac{65}{169})$

$(\frac{13}{169}, \frac{- 65}{169})$

$(\frac{9}{61}, \frac{23}{61})$

None

answer is C.

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Detailed Solution

S=0 represents a pairs of $⊥$ ’s lines
Ortho Centre= P.I of pair of lines

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