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Q.

The oscillating electric field of an electromagnetic wave is given by  EY=30sin[2×1011t+300πx] Vm1. Then, the value of wavelength of the electromagnetic wave is

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a

1250 m

b

1100 m

c

1150 m

d

150 m

answer is A.

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Detailed Solution

Given equation is  EY=30sin [2×1011t+300πx] Vm1
Comparing the given equation with the equation of  EY=E0sin[2πtT+2πxλ],

we get:
    2πλ=300π 1λ=150 λ=1150m

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The oscillating electric field of an electromagnetic wave is given by  EY=30sin[2×1011t+300πx] Vm−1. Then, the value of wavelength of the electromagnetic wave is