The oscillating magnetic field in a plane electromagnetic wave is given by $B_{y} = 5 \times 10^{- 6} \sin 1000 π (5 x - 4 \times 10^{8} t) T$ . The amplitude of electric field will be :

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$15 \times 10^{2} {Vm}^{- 1}$

$5 \times 10^{- 6} {Vm}^{- 1}$

$16 \times 10^{12} {Vm}^{- 1}$

$4 \times 10^{2} {Vm}^{- 1}$

answer is D.

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Detailed Solution

$\begin{array}{l} B_{0} = 5 \times 10^{- 6} \\ v = Speed of wave = \frac{4 \times 10^{8}}{5} = 8 \times 10^{7} [∴ v = \frac{W}{k}] \\ E_{0} = {vB}_{0} = 40 \times 10^{1} \\ = 4 \times 10^{2} V / m \end{array}$

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