The oscillating magnetic field in a plane electromagnetic wave is given by By=5×10−6 sin 1000π5x−4×108t T. The amplitude of electric field will be :

B0=5×10−6v= Speed of wave =4×1085=8×107 ∴v=WkE0=vB0=40×101=4×102 V/m

The oscillating magnetic field in a plane electromagnetic wave is given by By=5×10−6 sin 1000π5x−4×108t T. The amplitude of electric field will be :

B0=5×10−6v= Speed of wave =4×1085=8×107 ∴v=WkE0=vB0=40×101=4×102 V/m

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The oscillating magnetic field in a plane electromagnetic wave is given by $B_{y} = 5 \times 10^{- 6} \sin 1000 π (5 x - 4 \times 10^{8} t) T$ . The amplitude of electric field will be :

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$5 \times 10^{- 6} {Vm}^{- 1}$

$15 \times 10^{2} {Vm}^{- 1}$

$16 \times 10^{12} {Vm}^{- 1}$

$4 \times 10^{2} {Vm}^{- 1}$

answer is D.

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$\begin{array}{l} B_{0} = 5 \times 10^{- 6} \\ v = Speed of wave = \frac{4 \times 10^{8}}{5} = 8 \times 10^{7} [∴ v = \frac{W}{k}] \\ E_{0} = {vB}_{0} = 40 \times 10^{1} \\ = 4 \times 10^{2} V / m \end{array}$

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The oscillating magnetic field in a plane electromagnetic wave is given by By=5×10−6 sin 1000π5x−4×108t T. The amplitude of electric field will be :

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The oscillating magnetic field in a plane electromagnetic wave is given by $B_{y} = 5 \times 10^{- 6} \sin 1000 π (5 x - 4 \times 10^{8} t) T$ . The amplitude of electric field will be :