The osmotic pressure of 1kg solution $\left(\mathrm{density}=1.02 \mathrm{g} {\mathrm{cm}}^{-3}\right)$ containing 50g of glucose $\left({\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6\right)$ at 300 k is

Wt of solution = m =1Kg 1000g

density d 1.02g/ml

$\therefore \mathrm{Volume}=\mathrm{V}=\frac{\mathrm{m}}{\mathrm{\alpha }}\left[\therefore \mathrm{d}=\frac{\mathrm{m}}{\mathrm{v}}\right]$

$=\frac{1000}{1.02}$

=980 ml

V= 0.98lit

Wt. of glucose= W =50g

GMW of Glucose =M =180g

Temperature T = 300K

$\mathrm{\pi V}=\frac{\mathrm{W}}{\mathrm{M}}\mathrm{ST}; \mathrm{\pi }=\frac{\mathrm{W}}{\mathrm{M}}\frac{\mathrm{ST}}{\mathrm{V}}$

$=\frac{50\times 0.0821\times 300}{180\times 0.98}$

=6.98129 atm$=6.98129\times 101.325 \mathrm{Kpa}(\therefore 1 \mathrm{atm}-101.325\mathrm{Kpa})$

= 707.379Kpa