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Q.

The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL–1 is _____(Molar mass of glucose = 180 g mol–1

R=0.083L bar K1mol1 ) (Nearest integer) 

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answer is 54.

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Detailed Solution

 π=C.R.T 7.47=C×0.083×300 C=0.3M =0.3×180gL1 =54gL1

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